Algebra and Trigonometry 10th Edition

NOTE: Gauss-Jordan elimination will reduce until the matrix is in reduced row-echelon form. $\begin{bmatrix} -2 & 6 & |-22\\ 1 & 2 & |-9\\ \end{bmatrix}$ ~ $\begin{bmatrix} -1 & 3 & |-11\\ 1 & 2 & |-9\\ \end{bmatrix}$ ~ $\begin{bmatrix} -1 & 3 & |-11\\ 0 & 5 & |-20\\ \end{bmatrix}$ ~ $\begin{bmatrix} -1 & 3 & |-11\\ 0 & 1 & |-4\\ \end{bmatrix}$ ~ $\begin{bmatrix} -1 & 0 & |1\\ 0 & 1 & |-4\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 0 & |-1\\ 0 & 1 & |-4\\ \end{bmatrix}$ From reduced row-echelon form the solution is simple: x = -1 y = -4