Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 37

Answer

$8x+13y=0$

Work Step by Step

$(0,0)$ and $(-\frac{1}{8},\frac{1}{13})$ $m=\frac{\frac{1}{13}-0}{-\frac{1}{8}-0}=\frac{\frac{1}{13}}{-\frac{1}{8}}=-\frac{8}{13}$ $(y-y_1)=m(x-x_1)$ $(y-0)=-\frac{8}{13}(x-0)$ $y=-\frac{8}{13}x$ $13y=-8x$ $8x+13y=0$
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