Answer
$8x+13y=0$
Work Step by Step
$(0,0)$ and $(-\frac{1}{8},\frac{1}{13})$
$m=\frac{\frac{1}{13}-0}{-\frac{1}{8}-0}=\frac{\frac{1}{13}}{-\frac{1}{8}}=-\frac{8}{13}$
$(y-y_1)=m(x-x_1)$
$(y-0)=-\frac{8}{13}(x-0)$
$y=-\frac{8}{13}x$
$13y=-8x$
$8x+13y=0$