Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 34



Work Step by Step

$(-4,0)$ and $(6, -1)$ $m=\frac{-1-0}{6-(-4)}=\frac{-1}{10}=-\frac{1}{10}$ $(y-y_1)=m(x-x_1)$ $(y-0)=-\frac{1}{10}(x-(-4))$ $y=-\frac{1}{10}x-\frac{2}{5}$ $10y=-x-4$ $x+10y=-4$
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