Answer
$11x-8y=-3$
Work Step by Step
$(7,10)$ and $(-1,-1)$
$m=\frac{-1-10}{-1-7}=\frac{-11}{-8}=\frac{11}{8}$
$(y-y_1)=m(x-x_1)$
$(y-10)=\frac{11}{8}(x-7)$
$y-10=\frac{11}{8}x-\frac{77}{8}$
$8y-80=11x-77$
$11x-8y=-3$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 36
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