Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 36



Work Step by Step

$(7,10)$ and $(-1,-1)$ $m=\frac{-1-10}{-1-7}=\frac{-11}{-8}=\frac{11}{8}$ $(y-y_1)=m(x-x_1)$ $(y-10)=\frac{11}{8}(x-7)$ $y-10=\frac{11}{8}x-\frac{77}{8}$ $8y-80=11x-77$ $11x-8y=-3$
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