## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 12

#### Answer

Refer to the image below for the graph. #### Work Step by Step

Write the equation in $y=mx+b$ by isolating $y$ on one side of the equation: \begin{array}{ccc} &x&=&\frac{3}{2}y \\&\frac{2}{3} \cdot x&=&\frac{2}{3} \cdot \frac{3}{2}y \\&\frac{2}{3}x&=&y \\&y &=&\frac{2}{3}x \end{array} The given equation has: slope = $\dfrac{2}{3}\\$ y-intercept = $0$ To graph the equation, perform the following steps: (1) Plot the y-intercept point $(0, 0)$. (2) From $(0, 0)$, use the slope to locate another point. Move 2 units up (the rise) and 3 units to the right (the run) to end at the point $(3, 2)$. (3) Connect the two points using a straight line to complete the graph. (refer to the attached image in the answer part for the graph)

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