Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 35

Answer

$4x-3y=-1$

Work Step by Step

$(2,3)$ and $(-1,-1)$ $m=\frac{-1-3}{-1-2}=\frac{-4}{-3}=\frac{4}{3}$ $(y-y_1)=m(x-x_1)$ $(y-3)=\frac{4}{3}(x-2)$ $y-3=\frac{4}{3}x-\frac{8}{3}$ $3y-9=4x-8$ $4x-3y=-1$
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