Answer
$4x-3y=-1$
Work Step by Step
$(2,3)$ and $(-1,-1)$
$m=\frac{-1-3}{-1-2}=\frac{-4}{-3}=\frac{4}{3}$
$(y-y_1)=m(x-x_1)$
$(y-3)=\frac{4}{3}(x-2)$
$y-3=\frac{4}{3}x-\frac{8}{3}$
$3y-9=4x-8$
$4x-3y=-1$
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