Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 23

Answer

$6x-y=10$

Work Step by Step

We use the general form: $(y-y_1)=m(x-x_1)$. $(y-2)=(6)(x-2)$ $y-2=6x-12$ $6x-y=10$
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