Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set - Page 211: 9


$x+y=1$ Substituting $x=0$, $(0)+y=1$ $y=1$ Hence, (0,1) is a point on the graph. $x+y=1$ Substituting $x=1$, $(1)+y=1$ $y=0$ Hence, (1,0) is a point on the graph.

Work Step by Step

To graph this equation, we find two ordered pair solutions of $x+y=1$. To do this, we choose a value for one variable, x or y, and solve for the other variable. For example, if we let x=0 then $x+y=1$ becomes $x+y=1$ $(0)+y=1$ $y=1$ Since $y=1$ when $x=0$, the ordered pair (0, 1) is a solution of $x+y=1$ Next, we let x=1 $x+y=1$ $(1)+y=1$ $y=0$ The ordered pair (1, 0) is a second solution. The two solutions found so far allow us to draw the straight line that is the graph of all solutions of $x+y=1$
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