## Algebra: A Combined Approach (4th Edition)

$x-y=4$ Point A: $x-y=4$ $(0)-y=4$ $-y=4$ $y=-4$ Point B: $x-y=4$ $x-(2)=4$ $x=4+2$ $x=6$ Point C: $x-y=4$ $(-1)-y=4$ $-y=4+1$ $-y=5$ $y=-5$
To get the coordinates of point A, substitute the given x-value of 0 into the given equation $x-y=4$ to get the y-value of y=-4. Hence, we know that when x is 0, y is -4. i.e (0,-4) is a point on the line. To get the coordinates of point B, substitute the given y-value of 2 into the given equation $x-y=4$ to get the x-value of x=6. Hence, we know that when y is 2, x is 6. i.e (6,2) is a point on the line. To get the coordinates of point C, substitute the given x-value of -1 into the given equation $x-y=4$ to get the y-value of y=5. Hence, we know that when x is -1, y is -5. i.e (-1,-5) is a point on the line. Find the three points using the x and y values that you found, i.e graph points A, B and C. Using a ruler, draw a straight line passing through all three points to graph the equation of $x-y=4$.