Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set - Page 211: 1

Answer

$x-y=6$ $x=y+6$ Point A: $x=y+6$ $x=(0)+6$ $x=6$ Point B: $x=y+6$ $(4)=y+6$ $4-6=y$ $y=-2$ Point C: $x=y+6$ $x=(-1)+6$ $x=5$
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Work Step by Step

To get the coordinates of point A, substitute the given y-value of 0 into the given equation $x+y=6$ to get the x-value of x=6. Hence, we know that when y is 0, x is 6. i.e (6,0) is a point on the line. To get the coordinates of point B, substitute the given x-value of 4 into the given equation $x+y=6$ to get the value of y=-2. Hence, we know that when x is 4, y is -2. i.e (4,-2) is a point on the line. To get the coordinates of point C, substitute the given y-value of -1 into the given equation $x+y=6$ to get the x-value of x=5. Hence, we know that when y is -1, x is 5. i.e (5,-1) is a point on the line. Using a ruler, draw a straight line passing through all three points to graph the equation.
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