Algebra: A Combined Approach (4th Edition)

Point A: $y=-5x$ $y=-5(1)$ $y=-5$ Point B: $y=-5x$ $y=-5(0)$ $y=0$ Point C: $y=-5x$ $y=-5(-1)$ $y=5$
To get the coordinates of point A, substitute the given x-value of 1 into the given equation $y=-5x$ to get the y-value of y=-5. Hence, we know that when x is 1, y is -5. i.e (1,-5) is a point on the line. To get the coordinates of point B, substitute the given x-value of 0 into the given equation $y=-5x$ to get the y-value of y=0. Hence, we know that when x is 0, y is also 0. i.e (0,0) is a point on the line. To get the coordinates of point C, substitute the given x-value of -1 into the given equation $y=-5x$ to get the y-value of y=5. Hence, we know that when x is -1, y is 5. i.e (-1,5) is a point on the line. Find the three points using the x and y values that you found, i.e graph points A, B and C. Using a ruler, draw a straight line passing through all three points to graph the equation of $y=-5x$.