#### Answer

Point A:
$y=\frac{1}{3}x$
$y=\frac{1}{3}\times(0)$
$y=0$
Point B:
$y=\frac{1}{3}x$
$y=\frac{1}{3}\times(6)$
$y=2$
Point C:
$y=\frac{1}{3}x$
$y=\frac{1}{3}\times(-3)$
$y=-1$

#### Work Step by Step

To get the coordinates of point A, substitute the given x-value of 0 into the given equation $y=\frac{1}{3}x$ to get the y-value of y=0. Hence, we know that when x is 0, y is 0. i.e (0,0) is a point on the line.
To get the coordinates of point B, substitute the given x-value of 6 into the given equation $y=\frac{1}{3}x$ to get the y-value of y=2. Hence, we know that when x is 6, y is 2. i.e (6,2) is a point on the line.
To get the coordinates of point C, substitute the given x-value of -3 into the given equation $y=\frac{1}{3}x$ to get the y-value of y=-1. Hence, we know that when x is -3, y is -1. i.e (-3,-1) is a point on the line.
Graph points A, B and C using their respective x and y values.. Using a ruler, draw a straight line passing through all three points to graph the equation of $y=\frac{1}{3}x$.