Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set: 7

Answer

Point A: $y=-4x+3$ $y=-4\times(0)+3$ $y=3$ Point B: $y=-4x+3$ $y=-4\times(1)+3$ $y=-1$ Point C: $y=-4x+3$ $y=-4\times(2)+3$ $y=-5$
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Work Step by Step

To get the coordinates of point A, substitute the given x-value of 0 into the given equation $y=-4x+3$ to get the y-value of y=3. Hence, we know that when x is 0, y is 3. i.e (0,3) is a point on the line. To get the coordinates of point B, substitute the given x-value of 1 into the given equation $y=-4x+3$ to get the y-value of y=-1. Hence, we know that when x is 1, y is -1. i.e (1,-1) is a point on the line. To get the coordinates of point C, substitute the given x-value of 2 into the given equation $y=-4x+3$ to get the y-value of y=-5. Hence, we know that when x is 2, y is -5. i.e (2,-5) is a point on the line. Graph points A, B and C using their respective x and y values. Using a ruler, draw a straight line passing through all three points to graph the equation of $y=-4x+3$.
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