Answer
$(-4, -3)$
Work Step by Step
$-2/(y+3)>2$
Denominator is zero when $y=-3$
$-2/(y+3)>2$
$-2*(y+3)/(y+3)>2*(y+3)$
$-2 > 2y+6$
$-8 > 2y$
$-8/2 > 2y/2$
$y < -4$
(-infinity, $-4)$
$(-4, -3)$
$(-3$, infinity)
Let $y=-10$, $y=-3.5$, $y=10$
$y=-10$
$-2/(y+3)>2$
$-2/(-10+3)>2$
$-2/(-7)>2$
$2/7 > 2$ (false)
$y=-3.5$
$-2/(y+3)>2$
$-2/(-3.5+3)>2$
$-2/(-.5)>2$
$4 > 2$ (true)
$y=10$
$-2/(y+3)>2$
$-2/(10+3)>2$
$-2/(13)>2$
$-2/13 > 2 (false)