Answer
$(-7, 2)$
Work Step by Step
$(x+7)/(x-2)<0$
Denominator is zero when $x=2$
$x+7=0$
$x=-7$
(-infinity, $-7)$
$(-7, 2)$
$(2$, infinity)
Let $x=-10$, $x=0$, $x=10$
$x=-10$
$(x+7)/(x-2)<0$
$(-10+7)/(-10-2)<0$
$-17/-12 < 0$
$17/12 < 0$ (false)
$x=0$
$(x+7)/(x-2)<0$
$(0+7)/(0-2)<0$
$7/-2 <0$
$-7/2 < 0$ (true)
$x=10$
$(x+7)/(x-2)<0$
$(10+7)/(10-2)<0$
$17/8 < 0$ (false)