Answer
$8-2\sqrt {10}+2\sqrt5-2\sqrt2$
Work Step by Step
$(\sqrt5 - \sqrt 2+1)^2$
$(\sqrt5 - \sqrt 2+1)*(\sqrt5 - \sqrt 2+1)$
$\sqrt5*\sqrt5+\sqrt5*(-\sqrt2)+\sqrt5*1+(-\sqrt2*\sqrt5)+(-\sqrt2*-\sqrt2)+(-\sqrt2*1)+1*\sqrt5+1*(-\sqrt2)+1*1)$
$\sqrt25-\sqrt {10}+\sqrt5-\sqrt {10}+\sqrt4-\sqrt2+\sqrt5-\sqrt2+1$
$5-\sqrt {10}+\sqrt5-\sqrt {10}+2-\sqrt2+\sqrt5-\sqrt2+1$
$8-\sqrt {10}+\sqrt5-\sqrt {10}-\sqrt2+\sqrt5-\sqrt2$
$8-2\sqrt {10}+\sqrt5-\sqrt2+\sqrt5-\sqrt2$
$8-2\sqrt {10}+2\sqrt5-2\sqrt2$
