Answer
$(\sqrt{2x+5}-1)^{2}=2x-2\sqrt{2x+5}+6$
Work Step by Step
$(\sqrt{2x+5}-1)^{2}$
Use the formula for squaring a binomial to evaluate this power. The formula is $(a-b)^{2}=a^{2}-2ab+b^{2}$. In this expression, $a=\sqrt{2x+5}$ and $b=1$.
Substitute the known values into the formula and simplify if possible:
$(\sqrt{2x+5}-1)^{2}=(\sqrt{2x+5})^{2}-2\sqrt{2x+5}+1=...$
$...=2x+5-2\sqrt{2x+5}+1=...$
$...=2x-2\sqrt{2x+5}+6$
