Answer
$\sqrt[3]{6x^{2}}-(3x+1)\sqrt[3]{3x}+3\sqrt[3]{2x}-9x-3$
Work Step by Step
$(\sqrt[3]{3x}+3)(\sqrt[3]{2x}-3x-1)$
Evaluate the product and simplify if possible:
$\sqrt[3]{6x^{2}}-3x\sqrt[3]{3x}-\sqrt[3]{3x}+3\sqrt[3]{2x}-9x-3=...$
$...=\sqrt[3]{6x^{2}}-(3x+1)\sqrt[3]{3x}+3\sqrt[3]{2x}-9x-3$
