Answer
$6+2\sqrt6-2\sqrt2 -2\sqrt3$
Work Step by Step
$(\sqrt2 +\sqrt3 -1)^2$
$(\sqrt2 +\sqrt3 -1)*(\sqrt2 +\sqrt3 -1)$
$\sqrt2*\sqrt 2+\sqrt2*\sqrt 3+\sqrt2 *(-1)+\sqrt3*\sqrt 2+\sqrt3*\sqrt 3+\sqrt3 *(-1)+(-1)*\sqrt 2+(-1)*\sqrt 3+(-1) *(-1)$
$\sqrt4+\sqrt6-\sqrt2 +\sqrt6+\sqrt9-\sqrt3-\sqrt 2-\sqrt 3+1$
$2+\sqrt6-\sqrt2 +\sqrt6+3-\sqrt3-\sqrt 2-\sqrt 3+1$
$2+2\sqrt6-\sqrt2 +3-2\sqrt3-\sqrt 2+1$
$2+2\sqrt6-2\sqrt2 +3-2\sqrt3+1$
$6+2\sqrt6-2\sqrt2 -2\sqrt3$
