Answer
$(\sqrt{3x+1}+2)^{2}=3x+4\sqrt{3x+1}+5$
Work Step by Step
$(\sqrt{3x+1}+2)^{2}$
Use the formula for squaring a binomial to evaluate this power. The formula is $(a+b)^{2}=a^{2}+2ab+b^{2}$. In this expression, $a=\sqrt{3x+1}$ and $b=2$.
Substitute the known values into the formula and simplify if possible:
$(\sqrt{3x+1}+2)^{2}=(\sqrt{3x+1})^{2}+4\sqrt{3x+1}+4=...$
$...=3x+1+4\sqrt{3x+1}+4=...$
$...=3x+4\sqrt{3x+1}+5$