Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set: 74

Answer

$(\sqrt{3x+1}+2)^{2}=3x+4\sqrt{3x+1}+5$

Work Step by Step

$(\sqrt{3x+1}+2)^{2}$ Use the formula for squaring a binomial to evaluate this power. The formula is $(a+b)^{2}=a^{2}+2ab+b^{2}$. In this expression, $a=\sqrt{3x+1}$ and $b=2$. Substitute the known values into the formula and simplify if possible: $(\sqrt{3x+1}+2)^{2}=(\sqrt{3x+1})^{2}+4\sqrt{3x+1}+4=...$ $...=3x+1+4\sqrt{3x+1}+4=...$ $...=3x+4\sqrt{3x+1}+5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.