Answer
$\dfrac{14r-28r^{2}s^{2}}{7rs}=\dfrac{2(1-2rs^{2})}{s}$
Work Step by Step
$\dfrac{14r-28r^{2}s^{2}}{7rs}$
Take out common factor $14r$ from the numerator and simplify:
$\dfrac{14r-28r^{2}s^{2}}{7rs}=\dfrac{14r(1-2rs^{2})}{7rs}=\dfrac{2(1-2rs^{2})}{s}$