Answer
$\sqrt[4]{162x^{7}y^{20}}=3xy^{5}\sqrt[4]{2x^{3}}$
Work Step by Step
$\sqrt[4]{162x^{7}y^{20}}$
Take the fourth root of each factor and simplify:
$\sqrt[4]{162x^{7}y^{20}}=\sqrt[4]{162}\cdot\sqrt[4]{x^{7}}\cdot\sqrt[4]{y^{20}}=(3\sqrt[4]{2})(x\sqrt[4]{x^{3}})(y^{5})=...$
$...=3xy^{5}\sqrt[4]{2x^{3}}$
