# Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set - Page 703: 60

$\sqrt[4]{162x^{7}y^{20}}=3xy^{5}\sqrt[4]{2x^{3}}$

#### Work Step by Step

$\sqrt[4]{162x^{7}y^{20}}$ Take the fourth root of each factor and simplify: $\sqrt[4]{162x^{7}y^{20}}=\sqrt[4]{162}\cdot\sqrt[4]{x^{7}}\cdot\sqrt[4]{y^{20}}=(3\sqrt[4]{2})(x\sqrt[4]{x^{3}})(y^{5})=...$ $...=3xy^{5}\sqrt[4]{2x^{3}}$

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