Answer
$2y^{2}\sqrt[3] {2y}$
Work Step by Step
$\sqrt[3] {16y^{7}}=\sqrt[3] {16y^{6}y}=\sqrt[3] {16}\sqrt[3] {y^{6}}\sqrt[3] {y}=y^{2}\sqrt[3] {8*2}\sqrt[3] {y}=2y^{2}\sqrt[3] {2y}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set - Page 703: 41
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