## Algebra: A Combined Approach (4th Edition)

$\sqrt[4]{32x^{12}y^{5}}=2x^{3}y\sqrt[4]{2y}$
$\sqrt[4]{32x^{12}y^{5}}$ Take the fourth root of each factor and simplify: $\sqrt[4]{32x^{12}y^{5}}=\sqrt[4]{32}\cdot\sqrt[4]{x^{12}}\cdot\sqrt[4]{y^{5}}=(2\sqrt[4]{2})(x^{3})(y\sqrt[4]{y})=2x^{3}y\sqrt[4]{2y}$