Answer
$-\frac{{z^2}\sqrt[3] z}{5x}$
Work Step by Step
$-\sqrt[3] \frac{{z^7}}{{125x^3}}=-\frac{\sqrt[3] {z^6}\sqrt[3] z}{\sqrt[3] {125}\sqrt[3]{x^3}}=-\frac{{z^2}\sqrt[3] z}{5x}$
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