Answer
$2z^{2}\sqrt[5] {z^{2}}$
Work Step by Step
$\sqrt[5] {32z^{12}}=\sqrt[5] {32}\sqrt[5] {z^{10}}\sqrt[5] {z^{2}}=2z^{2}\sqrt[5] {z^{2}}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set - Page 703: 44
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