Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix G - Exercise Set - Page 1016: 1


Vertex=(0,0) 1st x-intercept=(0,0) 2nd x-intercept=(0,0)

Work Step by Step

Our function is $f(x)=3|x|$ We can write the function in the form f(x)=a|x−h|+k We can conclude that: $a=3$ $h=0$ $k=0$ $Vertex=(h,k)=(0,0)$ To find the x-intercepts we substitute y for 0. $0=3|x|$ Then you solve the equation. Divide 3 on both sides $0=|x|$ Two possibilities: possibility 1: $x=0$ possibility 2: $x=0$ Therefore the 2 x-intercepts are $(0,0)$ and $(0,0)$
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