## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Appendix G - Exercise Set - Page 1016: 2

#### Answer

Vertex:$(0,0)$ 1st x-intercept:$(0,0)$ 2nd x-intercept:$(0,0)$

#### Work Step by Step

Our function is $f(x)=5|x|$ We can write the function in the form $f(x)=a|x−h|+k$ We can conclude that: $a=5$ $h=0$ $k=0$ $Vertex=(h,k)=(0,0)$ To find the x-intercepts we substitute y for 0. $0=5|x|$ Then you solve the equation. Divide 5 on both sides $0=|x|$ Two possibilities: possibility 1: $x=0$ possibility 2: $x=0$ Therefore the 2 x-intercepts are $(0,0)$ and $(0,0)$ To graph the function use the slope which is 5, and with the slope and the vertex, you can graph the function.

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