Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix G - Exercise Set - Page 1016: 5


Vertex=(0,0) 1st x-intercept=(0,0) 2nd x-intercept=(0,0)

Work Step by Step

Our function is $f(x)=2|x|+3$ We can write the function in the form $f(x)=a|x−h|+k$ We can conclude that: $a=2$ $h=0$ $k=3$ $Vertex=(h,k)=(0,3)$ To find the x-intercepts we substitute y for 0. $0=2|x|+3$ Then you solve the equation. Subtract 3 on both sides $-3=2|x|$ Divide 2 on both sides $=|x|$ Two possibilities: possibility 1: $x=0$ possibility 2: $x=0$ Therefore the 2 x-intercepts are $(0,0)$ and $(0,0)$
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