Answer
Vertex=(0,0)
1st x-intercept=(0,0)
2nd x-intercept=(0,0)
Work Step by Step
Our function is $f(x)=\frac{1}{3}|x|$
We can write the function in the form $f(x)=a|x−h|+k$
We can conclude that:
$a=\frac{1}{3}$
$h=0$
$k=0$
$Vertex=(h,k)=(0,0)$
To find the x-intercepts we substitute y for 0.
$0=\frac{1}{3}|x|$
Then you solve the equation.
Multiply 3 on both sides
$0=|x|$
Two possibilities:
possibility 1:
$x=0$
possibility 2:
$x=0$
Therefore the 2 x-intercepts are $(0,0)$ and $(0,0)$
