Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix G - Practice - Page 1015: 2


Vertex=$(-1,3)$ 1st x-intercept=$(-7,0)$ 2nd x-intercept=$(5,0)$

Work Step by Step

Our function is $f(x)=-\frac{1}{2}|x+1|+3$ We can write the function in the form $f(x)=a|x-h|+k$ We can conclude that: $a=-\frac{1}{2}$ $h=-1$ $k=3$ Vertex=$(h,k)=(-1,3)$ To find the x-intercepts we substitute y for 0. $0=-\frac{1}{2}|x+1|+3$ Then you solve the equation. Subtract 3 from both sides. $-3=-\frac{1}{2}|x+1|$ Divide by $-\frac{1}{2}$ on both sides $6=|x+1|$ Two possibilities: possibility 1: $6=x+1$ x=5 possibility 2: $6=-x-1$ 7=-x x=-7 Therefore the 2 x-intercepts are $(-7,0)$ and $(5,0)$ Graph the vertex and the two x-intercepts on a graph and connect the x-intercepts with the vertex.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.