Answer
$\dfrac{\log_{10}{3.3}}{\log_{10}{9}}$ or $\dfrac{\log{3.3}}{\log9}$
Work Step by Step
Recall the change of base formula (pg. 464):
$\log_{b}{m}=\frac{\log_{c}{m}}{\log_{c}{b}}$
Applying this formula to our equation ($b=9, m=3.3, c=10$), we get:
$\log_9{3.3}=\dfrac{\log_{10}{3.3}}{\log_{10}{9}}$