Answer
$log$ ${s}$ + $\frac{1}{2}$ $log$ ${7}$ - $2$ $log$ ${t}$
Work Step by Step
Use the Quotient Property of Logarithms. According to this property, $log_b$ ${m}$ - $log_b$ ${n}$ = $log_b$ $\frac {m}{n}$:
$log$ ${s\sqrt {7}}$ - $log$ ${t^{2}}$
Use the Product Property of Logarithms. According to this property, $log_b$ ${mn}$ = $log_b$ ${m}$ + $log_b$ ${n}$:
$log$ ${s}$ + $log$ ${\sqrt {7}}$ - $log$ ${t^{2}}$
Convert the radical term to an exponential one:
$log$ ${s}$ + $log$ ${7^{\frac{1}{2}}}$ - $log$ ${t^{2}}$
Use the Power Property of Logarithms to rewrite this expression. The property states that $log_b$ ${m^n}$ = $n$ $log_b$ ${m}$:
$log$ ${s}$ + $\frac{1}{2}$ $log$ ${7}$ - $2$ $log$ ${t}$
