Answer
$\dfrac{\log_{10}{8}}{\log_{10}{3}}$ or $\dfrac{\log8}{\log3}$
Work Step by Step
Recall the change of base formula (pg. 464):
$\log_{b}{m}=\frac{\log_{c}{m}}{\log_{c}{b}}$
Applying this formula to our equation ($b=3, m=8, c=10$), we get:
$\log_3{8}=\dfrac{\log_{10}{8}}{\log_{10}{3}}$
