Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-4 Properties of Logarithms - Practice and Problem-Solving Exercises - Page 467: 50

Answer

True

Work Step by Step

We are given the following expression: $\log_2{4}+\log_2{8}\stackrel{?}{=}5$ Recall the product property of logarithms (pg. 462): $\log_b{mn}=\log_b{m}+\log_b{n}$ Applying this property to the left side, we obtain: $\log_2{4}+\log_2{8}=\log_2{4\cdot8}=\log_2{32}$ Next, recall the power property of logarithms (pg. 462): $\log_b{m^n}=n\log_b{m}$ We apply this to our last expression: $\log_2{32}=\log_2{2^5}=5\log_2{2}=5\times 1=5$ We used the fact that $\log_{5}{5}=1$ (because $5^1=5$). Thus we see that the expression is True.
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