Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 50


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Work Step by Step

Given: $\log_2(x+1)=\log_8 3x\\\log_2(x+1)=\frac{\log_2 3x}{\log_2 8}\\\log_2(x+1)=\frac{\log_2 3x}{3}\\3\log_2(x+1)=\log_2 3x\\\log_2(x+1)^3=\log_23x\\(x+1)^3=3x\\x^3+3x^2+3x+1=3x\\x^3+3x^2+1=0\\x\approx-3.1038$
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