Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 40

Answer

$$x=-e^{\frac{9}{2}}$$

Work Step by Step

Using the rules of logarithms to solve the equation, we find: $$4\ln \left(-x\right)=18 \\ \ln \left(-x\right)=\frac{9}{2} \\ x=-e^{\frac{9}{2}}$$ Checking for extraneous solutions, we see that the solution is valid.
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