Answer
A
Work Step by Step
Using the rules of logarithms to solve the equation, we find:
$$\log _8\left(2x+7\right)=\frac{2}{3} \\ \log _8\left(2x+7\right)=\log _8\left(4\right) \\ 2x+7=4 \\ x=-\frac{3}{2}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 44
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