Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 42

Answer

9

Work Step by Step

Using the rules of logarithms to solve the equation, we find: $$\log _6\left(3x\left(x-1\right)\right)=3 \\ 3x\left(x-1\right)=216 \\ x=9,\:x=-8$$ Checking for extraneous solutions, we see that only $x=9$ is valid.
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