## Algebra 2 (1st Edition)

Using the rules of logarithms to solve the equation, we find: $$\log _6\left(3x\left(x-1\right)\right)=3 \\ 3x\left(x-1\right)=216 \\ x=9,\:x=-8$$ Checking for extraneous solutions, we see that only $x=9$ is valid.