# Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 23

-.203

#### Work Step by Step

Using natural logarithms to solve this problem, we find: $$e^{2x} =\frac{2}{3} \\ 2x = ln(\frac{2}{3}) \\ x = -.203$$

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