Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Skill Practice - Page 520: 45


The log of 6 base 3 is not equal to two, so the student was incorrect.

Work Step by Step

Using the rules of logarithms to solve the equation, we find: $$\ln \left(3^{x+1}\right)=\ln \left(6^x\right) \\ \left(x+1\right)\ln \left(3\right)=x\ln \left(6\right) \\ x=\frac{\ln \left(3\right)}{\ln \left(2\right)} \\ x=1.58$$
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