Algebra 2 (1st Edition)

Using the rules of logarithms to solve the equation, we find: $$\ln \left(3^{x+1}\right)=\ln \left(6^x\right) \\ \left(x+1\right)\ln \left(3\right)=x\ln \left(6\right) \\ x=\frac{\ln \left(3\right)}{\ln \left(2\right)} \\ x=1.58$$