Answer
The log of 6 base 3 is not equal to two, so the student was incorrect.
Work Step by Step
Using the rules of logarithms to solve the equation, we find:
$$\ln \left(3^{x+1}\right)=\ln \left(6^x\right) \\ \left(x+1\right)\ln \left(3\right)=x\ln \left(6\right) \\ x=\frac{\ln \left(3\right)}{\ln \left(2\right)} \\ x=1.58$$
