Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Chapter Review - 9-1 and 9-2 Graphing Quadratic Functions - Page 590: 9

Answer

Please see the graph.
1534826093

Work Step by Step

$y=-.5x^2+4x+1$ vertex $x=-b/2a$ $x=-4/2*-.5$ $x=-4/-1 = 4$ $y=-.5x^2+4x+1$ $y=-.5*4^2+4*4+1$ $y=-.5*16+16+1$ $y=-8+17$ $y=9$ $(4,9)$ One other point on the line $x=0$ $y=-.5x^2+4x+1$ $y=-.5*0^2+4*0+1$ $y=-.5*0+0+1$ $y=0+0+1 = 1$ $(0,1)$ The vertex is labeled, and the axis of symmetry is the blue line.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.