Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Chapter Review - 9-1 and 9-2 Graphing Quadratic Functions - Page 590: 10

Answer

Please see the grtaph
1534826445

Work Step by Step

$y=-2x^2-3x+10$ vertex: $x=-b/2a$ $x=-(-3)/2*(-2)$ $x=3/-4 = -3/4$ $y=-2x^2-3x+10$ $y=-2*.75^2-3*.75+10$ $y=-2*.5625-2.25+10$ $y=-1.125+7.75$ $y=6.625$ $(-.75, 6.625)$ One other point on the curve $x=0$ $y=-2x^2-3x+10$ $y=-2*0^2-3*0+10$ $y=-2*0-0+10$ $y=0+10 = 10$ $(0,10)$ The vertex is labeled, and the axis of symmetry is the blue line.
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