## Algebra 1

Published by Prentice Hall

# Chapter 9 - Quadratic Functions and Equations - Chapter Review - 9-1 and 9-2 Graphing Quadratic Functions - Page 590: 11

#### Answer

Please see the graph.

#### Work Step by Step

$y=.5x^2+2x-3$ vertex: $x=-b/2a$ $x=-(2)/2(.5)$ $x=-2/1 = -2$ $y=.5x^2+2x-3$ $y=.5*(-2)^2+2*(-2)-3$ $y=.5*4+(-4)-3$ $y=2-4-3$ $y=-5$ $(-2, -5)$ One other point on the curve: $x=0$ $y=.5x^2+2x-3$ $y=.5(0)^2+2*0-3$ $y=.5*0+0-3$ $y=0-3 = -3$ $(0,-3)$ The blue line is the axis of symmetry, and the vertex is labeled.

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