## Algebra 1

$y=2/3*x^2$ vertex: $x=-b/2a$ $x=-0/2*2/3$ $x=0$ $y=2/3*x^2$ $y=2/3*(0)^2$ $y=2/3*0=0$ $(0,0)$ One other point on the graph: $x=3$ $y=2/3*x^2$ $y=2/3*3^2$ $y=2/3*9=6$ $(3,6)$ The axis of symmetry is the blue line, and the vertex is labeled.