Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 32

Answer

$s^2=169$ $s=13$

Work Step by Step

$s^2=169$ $\sqrt {169} = \sqrt {s^2}$ $s= 13, -13$ We can't have a negative sidelength, so $s=13$
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