Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 24


$$p = \pm12$$

Work Step by Step

First you subtract 144 from both sides $$-p^2 = -144$$ Then you divide by -1 on both sides $$p^2 = 144$$ Then you find the square root of both sides $$p= \pm12$$ That is your final answer since the variable is alone now. Remember you always have to put the plus or minus sign ($\pm$) because any number under the square root that is above $0$ has $2$ has answers.
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