Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 25


No Solution

Work Step by Step

First you subtract 12 from both sides $$3a^2 = -12$$ Then you divide 3 from both sides $$a^2 = -3$$ The next step is to find the square root of both sides but since there is a negative on the right side of the equation, there is no solution because you can't have a negative under a square root.
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