Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 26

Answer

$$z = \pm3$$

Work Step by Step

First you add 45 to both sides $$5z^2 = 45$$ Then you divide both sides by 5 $$z^2 = 9$$ Then you find the square root of both sides $$z = \pm3$$ That is your final answer since the variable is alone now. Remember you always have to put the plus or minus sign ($\pm$) because any number under the square root that is above $0$ has $2$ has answers. And you can multiply the negative version of the number by itself to get the number that is under the square root.
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