## Algebra 1

$x^{2}$ + 5 = 5 We subtract 5 from both sides and we get $x^{2}$ = 0 We take the square root of both sides $\sqrt x^{2} = \sqrt 0$ $\sqrt 0$ = 0 because 0 x 0 = 0 thus x=0 which is only one solution. Therefore there is only one solution present.